(8x+1)^1/2=5

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Solution for (8x+1)^1/2=5 equation:


x in (-oo:+oo)

((8*x+1)^1)/2 = 5 // - 5

((8*x+1)^1)/2-5 = 0

(8*x+1)/2-5 = 0

(8*x+1)/2+(-5*2)/2 = 0

8*x-5*2+1 = 0

8*x-9 = 0

(8*x-9)/2 = 0

(8*x-9)/2 = 0 // * 2

8*x-9 = 0

8*x-9 = 0 // + 9

8*x = 9 // : 8

x = 9/8

x = 9/8

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